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Data.Time.Calendar.Julian |
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Synopsis |
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Year and day format
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convert to proleptic Julian year and day format. First element of result is year (proleptic Julian calendar),
second is the day of the year, with 1 for Jan 1, and 365 (or 366 in leap years) for Dec 31.
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convert from proleptic Julian year and day format.
Invalid day numbers will be clipped to the correct range (1 to 365 or 366).
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convert from proleptic Julian year and day format.
Invalid day numbers will return Nothing
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show in proleptic Julian year and day format (yyyy-ddd)
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Is this year a leap year according to the proleptic Julian calendar?
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convert to proleptic Julian calendar. First element of result is year, second month number (1-12), third day (1-31).
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convert from proleptic Julian calendar. First argument is year, second month number (1-12), third day (1-31).
Invalid values will be clipped to the correct range, month first, then day.
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convert from proleptic Julian calendar. First argument is year, second month number (1-12), third day (1-31).
Invalid values will return Nothing.
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show in ISO 8601 format (yyyy-mm-dd)
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The number of days in a given month according to the proleptic Julian calendar. First argument is year, second is month.
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Add months, with days past the last day of the month clipped to the last day.
For instance, 2005-01-30 + 1 month = 2005-02-28.
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Add months, with days past the last day of the month rolling over to the next month.
For instance, 2005-01-30 + 1 month = 2005-03-02.
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Add years, matching month and day, with Feb 29th clipped to Feb 28th if necessary.
For instance, 2004-02-29 + 2 years = 2006-02-28.
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Add years, matching month and day, with Feb 29th rolled over to Mar 1st if necessary.
For instance, 2004-02-29 + 2 years = 2006-03-01.
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Produced by Haddock version 2.4.2 |