Data.IntMap

O(min(n,W)). Insert a new key/value pair in the map. If the key is already present in the map, the associated value is replaced with the supplied value, i.e. insert is equivalent to insertWith const.

insertWith :: (a -> a -> a) -> Key -> a -> IntMap a -> IntMap a

O(min(n,W)). Insert with a combining function.

insertWithKey :: (Key -> a -> a -> a) -> Key -> a -> IntMap a -> IntMap a

O(min(n,W)). Insert with a combining function.

insertLookupWithKey :: (Key -> a -> a -> a) -> Key -> a -> IntMap a -> (Maybe a, IntMap a)

O(min(n,W)). The expression (insertLookupWithKey f k x map) is a pair where the first element is equal to (lookup k map) and the second element equal to (insertWithKey f k x map).

Delete/Update

delete :: Key -> IntMap a -> IntMap a

O(min(n,W)). Delete a key and its value from the map. When the key is not a member of the map, the original map is returned.

adjust :: (a -> a) -> Key -> IntMap a -> IntMap a

O(min(n,W)). Adjust a value at a specific key. When the key is not a member of the map, the original map is returned.

adjustWithKey :: (Key -> a -> a) -> Key -> IntMap a -> IntMap a

O(min(n,W)). Adjust a value at a specific key. When the key is not a member of the map, the original map is returned.

update :: (a -> Maybe a) -> Key -> IntMap a -> IntMap a

O(min(n,W)). The expression (update f k map) updates the value x at k (if it is in the map). If (f x) is Nothing, the element is deleted. If it is (Just y), the key k is bound to the new value y.

updateWithKey :: (Key -> a -> Maybe a) -> Key -> IntMap a -> IntMap a

O(min(n,W)). The expression (update f k map) updates the value x at k (if it is in the map). If (f k x) is Nothing, the element is deleted. If it is (Just y), the key k is bound to the new value y.

updateLookupWithKey :: (Key -> a -> Maybe a) -> Key -> IntMap a -> (Maybe a, IntMap a)

O(min(n,W)). Lookup and update.

Combine

Union

union :: IntMap a -> IntMap a -> IntMap a

O(n+m). The (left-biased) union of two maps. It prefers the first map when duplicate keys are encountered, i.e. (union == unionWith const).

unionWith :: (a -> a -> a) -> IntMap a -> IntMap a -> IntMap a

O(n+m). The union with a combining function.

unionWithKey :: (Key -> a -> a -> a) -> IntMap a -> IntMap a -> IntMap a

O(n+m). The union with a combining function.

unions :: [IntMap a] -> IntMap a

The union of a list of maps.

unionsWith :: (a -> a -> a) -> [IntMap a] -> IntMap a

The union of a list of maps, with a combining operation

Difference

difference :: IntMap a -> IntMap b -> IntMap a

O(n+m). Difference between two maps (based on keys).

differenceWith :: (a -> b -> Maybe a) -> IntMap a -> IntMap b -> IntMap a

O(n+m). Difference with a combining function.

differenceWithKey :: (Key -> a -> b -> Maybe a) -> IntMap a -> IntMap b -> IntMap a

O(n+m). Difference with a combining function. When two equal keys are encountered, the combining function is applied to the key and both values. If it returns Nothing, the element is discarded (proper set difference). If it returns (Just y), the element is updated with a new value y.

Intersection

intersection :: IntMap a -> IntMap b -> IntMap a

O(n+m). The (left-biased) intersection of two maps (based on keys).

intersectionWith :: (a -> b -> a) -> IntMap a -> IntMap b -> IntMap a

O(n+m). The intersection with a combining function.

intersectionWithKey :: (Key -> a -> b -> a) -> IntMap a -> IntMap b -> IntMap a

O(n+m). The intersection with a combining function.

Traversal

Map

map :: (a -> b) -> IntMap a -> IntMap b

O(n). Map a function over all values in the map.

mapWithKey :: (Key -> a -> b) -> IntMap a -> IntMap b

O(n). Map a function over all values in the map.

mapAccum :: (a -> b -> (a, c)) -> a -> IntMap b -> (a, IntMap c)

O(n). The function mapAccum threads an accumulating argument through the map in ascending order of keys.

mapAccumWithKey :: (a -> Key -> b -> (a, c)) -> a -> IntMap b -> (a, IntMap c)

O(n). The function mapAccumWithKey threads an accumulating argument through the map in ascending order of keys.

Fold

fold :: (a -> b -> b) -> b -> IntMap a -> b

O(n). Fold the values in the map, such that fold f z == foldr f z . elems. For example,

 elems map = fold (:) [] map

foldWithKey :: (Key -> a -> b -> b) -> b -> IntMap a -> b

O(n). Fold the keys and values in the map, such that foldWithKey f z == foldr (uncurry f) z . toAscList. For example,

 keys map = foldWithKey (\k x ks -> k:ks) [] map

Conversion

elems :: IntMap a -> [a]

O(n). Return all elements of the map in the ascending order of their keys.

keys :: IntMap a -> [Key]

O(n). Return all keys of the map in ascending order.

keysSet :: IntMap a -> IntSet

O(n*min(n,W)). The set of all keys of the map.

assocs :: IntMap a -> [(Key, a)]

O(n). Return all key/value pairs in the map in ascending key order.

Lists

toList :: IntMap a -> [(Key, a)]

O(n). Convert the map to a list of key/value pairs.

fromList :: [(Key, a)] -> IntMap a

O(n*min(n,W)). Create a map from a list of key/value pairs.

fromListWith :: (a -> a -> a) -> [(Key, a)] -> IntMap a

O(n*min(n,W)). Create a map from a list of key/value pairs with a combining function. See also fromAscListWith.

fromListWithKey :: (Key -> a -> a -> a) -> [(Key, a)] -> IntMap a

O(n*min(n,W)). Build a map from a list of key/value pairs with a combining function. See also fromAscListWithKey'.

Ordered lists

toAscList :: IntMap a -> [(Key, a)]

O(n). Convert the map to a list of key/value pairs where the keys are in ascending order.

fromAscList :: [(Key, a)] -> IntMap a

O(n*min(n,W)). Build a map from a list of key/value pairs where the keys are in ascending order.

fromAscListWith :: (a -> a -> a) -> [(Key, a)] -> IntMap a

O(n*min(n,W)). Build a map from a list of key/value pairs where the keys are in ascending order, with a combining function on equal keys.

fromAscListWithKey :: (Key -> a -> a -> a) -> [(Key, a)] -> IntMap a

O(n*min(n,W)). Build a map from a list of key/value pairs where the keys are in ascending order, with a combining function on equal keys.

fromDistinctAscList :: [(Key, a)] -> IntMap a

O(n*min(n,W)). Build a map from a list of key/value pairs where the keys are in ascending order and all distinct.

Filter

filter :: (a -> Bool) -> IntMap a -> IntMap a

O(n). Filter all values that satisfy some predicate.

filterWithKey :: (Key -> a -> Bool) -> IntMap a -> IntMap a

O(n). Filter all keys/values that satisfy some predicate.

partition :: (a -> Bool) -> IntMap a -> (IntMap a, IntMap a)

O(n). partition the map according to some predicate. The first map contains all elements that satisfy the predicate, the second all elements that fail the predicate. See also split.

partitionWithKey :: (Key -> a -> Bool) -> IntMap a -> (IntMap a, IntMap a)

O(n). partition the map according to some predicate. The first map contains all elements that satisfy the predicate, the second all elements that fail the predicate. See also split.

split :: Key -> IntMap a -> (IntMap a, IntMap a)

O(log n). The expression (split k map) is a pair (map1,map2) where all keys in map1 are lower than k and all keys in map2 larger than k. Any key equal to k is found in neither map1 nor map2.

splitLookup :: Key -> IntMap a -> (IntMap a, Maybe a, IntMap a)

O(log n). Performs a split but also returns whether the pivot key was found in the original map.

Submap

isSubmapOf :: Eq a => IntMap a -> IntMap a -> Bool

O(n+m). Is this a submap? Defined as (isSubmapOf = isSubmapOfBy (==)).

isSubmapOfBy :: (a -> b -> Bool) -> IntMap a -> IntMap b -> Bool

O(n+m). The expression (isSubmapOfBy f m1 m2) returns True if all keys in m1 are in m2, and when f returns True when applied to their respective values. For example, the following expressions are all True:

 isSubmapOfBy (==) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
 isSubmapOfBy (<=) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
 isSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1),(2,2)])

But the following are all False:

 isSubmapOfBy (==) (fromList [(1,2)]) (fromList [(1,1),(2,2)])
 isSubmapOfBy (<) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
 isSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1)])

isProperSubmapOf :: Eq a => IntMap a -> IntMap a -> Bool

O(n+m). Is this a proper submap? (ie. a submap but not equal). Defined as (isProperSubmapOf = isProperSubmapOfBy (==)).

isProperSubmapOfBy :: (a -> b -> Bool) -> IntMap a -> IntMap b -> Bool

O(n+m). Is this a proper submap? (ie. a submap but not equal). The expression (isProperSubmapOfBy f m1 m2) returns True when m1 and m2 are not equal, all keys in m1 are in m2, and when f returns True when applied to their respective values. For example, the following expressions are all True:

 isProperSubmapOfBy (==) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
 isProperSubmapOfBy (<=) (fromList [(1,1)]) (fromList [(1,1),(2,2)])

But the following are all False:

 isProperSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1),(2,2)])
 isProperSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1)])
 isProperSubmapOfBy (<)  (fromList [(1,1)])       (fromList [(1,1),(2,2)])

Debugging

showTree :: Show a => IntMap a -> String

O(n). Show the tree that implements the map. The tree is shown in a compressed, hanging format.

showTreeWith :: Show a => Bool -> Bool -> IntMap a -> String

O(n). The expression (showTreeWith hang wide map) shows the tree that implements the map. If hang is True, a hanging tree is shown otherwise a rotated tree is shown. If wide is True, an extra wide version is shown.

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