Portability | portable |
---|---|
Stability | provisional |
Maintainer | libraries@haskell.org |
An efficient implementation of maps from keys to values (dictionaries).
Since many function names (but not the type name) clash with
Prelude names, this module is usually imported qualified
, e.g.
import Data.Map (Map) import qualified Data.Map as Map
The implementation of Map
is based on size balanced binary trees (or
trees of bounded balance) as described by:
- Stephen Adams, "Efficient sets: a balancing act", Journal of Functional Programming 3(4):553-562, October 1993, http://www.swiss.ai.mit.edu/~adams/BB/.
- J. Nievergelt and E.M. Reingold, "Binary search trees of bounded balance", SIAM journal of computing 2(1), March 1973.
Note that the implementation is left-biased -- the elements of a
first argument are always preferred to the second, for example in
union
or insert
.
Operation comments contain the operation time complexity in the Big-O notation http://en.wikipedia.org/wiki/Big_O_notation.
- data Map k a
- (!) :: Ord k => Map k a -> k -> a
- (\\) :: Ord k => Map k a -> Map k b -> Map k a
- null :: Map k a -> Bool
- size :: Map k a -> Int
- member :: Ord k => k -> Map k a -> Bool
- notMember :: Ord k => k -> Map k a -> Bool
- lookup :: Ord k => k -> Map k a -> Maybe a
- findWithDefault :: Ord k => a -> k -> Map k a -> a
- empty :: Map k a
- singleton :: k -> a -> Map k a
- insert :: Ord k => k -> a -> Map k a -> Map k a
- insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a
- insertWith' :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k a
- insertWithKey :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> Map k a
- insertWithKey' :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> Map k a
- insertLookupWithKey :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> (Maybe a, Map k a)
- insertLookupWithKey' :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> (Maybe a, Map k a)
- delete :: Ord k => k -> Map k a -> Map k a
- adjust :: Ord k => (a -> a) -> k -> Map k a -> Map k a
- adjustWithKey :: Ord k => (k -> a -> a) -> k -> Map k a -> Map k a
- update :: Ord k => (a -> Maybe a) -> k -> Map k a -> Map k a
- updateWithKey :: Ord k => (k -> a -> Maybe a) -> k -> Map k a -> Map k a
- updateLookupWithKey :: Ord k => (k -> a -> Maybe a) -> k -> Map k a -> (Maybe a, Map k a)
- alter :: Ord k => (Maybe a -> Maybe a) -> k -> Map k a -> Map k a
- union :: Ord k => Map k a -> Map k a -> Map k a
- unionWith :: Ord k => (a -> a -> a) -> Map k a -> Map k a -> Map k a
- unionWithKey :: Ord k => (k -> a -> a -> a) -> Map k a -> Map k a -> Map k a
- unions :: Ord k => [Map k a] -> Map k a
- unionsWith :: Ord k => (a -> a -> a) -> [Map k a] -> Map k a
- difference :: Ord k => Map k a -> Map k b -> Map k a
- differenceWith :: Ord k => (a -> b -> Maybe a) -> Map k a -> Map k b -> Map k a
- differenceWithKey :: Ord k => (k -> a -> b -> Maybe a) -> Map k a -> Map k b -> Map k a
- intersection :: Ord k => Map k a -> Map k b -> Map k a
- intersectionWith :: Ord k => (a -> b -> c) -> Map k a -> Map k b -> Map k c
- intersectionWithKey :: Ord k => (k -> a -> b -> c) -> Map k a -> Map k b -> Map k c
- map :: (a -> b) -> Map k a -> Map k b
- mapWithKey :: (k -> a -> b) -> Map k a -> Map k b
- mapAccum :: (a -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)
- mapAccumWithKey :: (a -> k -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)
- mapAccumRWithKey :: (a -> k -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)
- mapKeys :: Ord k2 => (k1 -> k2) -> Map k1 a -> Map k2 a
- mapKeysWith :: Ord k2 => (a -> a -> a) -> (k1 -> k2) -> Map k1 a -> Map k2 a
- mapKeysMonotonic :: (k1 -> k2) -> Map k1 a -> Map k2 a
- fold :: (a -> b -> b) -> b -> Map k a -> b
- foldWithKey :: (k -> a -> b -> b) -> b -> Map k a -> b
- foldrWithKey :: (k -> a -> b -> b) -> b -> Map k a -> b
- foldlWithKey :: (b -> k -> a -> b) -> b -> Map k a -> b
- elems :: Map k a -> [a]
- keys :: Map k a -> [k]
- keysSet :: Map k a -> Set k
- assocs :: Map k a -> [(k, a)]
- toList :: Map k a -> [(k, a)]
- fromList :: Ord k => [(k, a)] -> Map k a
- fromListWith :: Ord k => (a -> a -> a) -> [(k, a)] -> Map k a
- fromListWithKey :: Ord k => (k -> a -> a -> a) -> [(k, a)] -> Map k a
- toAscList :: Map k a -> [(k, a)]
- toDescList :: Map k a -> [(k, a)]
- fromAscList :: Eq k => [(k, a)] -> Map k a
- fromAscListWith :: Eq k => (a -> a -> a) -> [(k, a)] -> Map k a
- fromAscListWithKey :: Eq k => (k -> a -> a -> a) -> [(k, a)] -> Map k a
- fromDistinctAscList :: [(k, a)] -> Map k a
- filter :: Ord k => (a -> Bool) -> Map k a -> Map k a
- filterWithKey :: Ord k => (k -> a -> Bool) -> Map k a -> Map k a
- partition :: Ord k => (a -> Bool) -> Map k a -> (Map k a, Map k a)
- partitionWithKey :: Ord k => (k -> a -> Bool) -> Map k a -> (Map k a, Map k a)
- mapMaybe :: Ord k => (a -> Maybe b) -> Map k a -> Map k b
- mapMaybeWithKey :: Ord k => (k -> a -> Maybe b) -> Map k a -> Map k b
- mapEither :: Ord k => (a -> Either b c) -> Map k a -> (Map k b, Map k c)
- mapEitherWithKey :: Ord k => (k -> a -> Either b c) -> Map k a -> (Map k b, Map k c)
- split :: Ord k => k -> Map k a -> (Map k a, Map k a)
- splitLookup :: Ord k => k -> Map k a -> (Map k a, Maybe a, Map k a)
- isSubmapOf :: (Ord k, Eq a) => Map k a -> Map k a -> Bool
- isSubmapOfBy :: Ord k => (a -> b -> Bool) -> Map k a -> Map k b -> Bool
- isProperSubmapOf :: (Ord k, Eq a) => Map k a -> Map k a -> Bool
- isProperSubmapOfBy :: Ord k => (a -> b -> Bool) -> Map k a -> Map k b -> Bool
- lookupIndex :: Ord k => k -> Map k a -> Maybe Int
- findIndex :: Ord k => k -> Map k a -> Int
- elemAt :: Int -> Map k a -> (k, a)
- updateAt :: (k -> a -> Maybe a) -> Int -> Map k a -> Map k a
- deleteAt :: Int -> Map k a -> Map k a
- findMin :: Map k a -> (k, a)
- findMax :: Map k a -> (k, a)
- deleteMin :: Map k a -> Map k a
- deleteMax :: Map k a -> Map k a
- deleteFindMin :: Map k a -> ((k, a), Map k a)
- deleteFindMax :: Map k a -> ((k, a), Map k a)
- updateMin :: (a -> Maybe a) -> Map k a -> Map k a
- updateMax :: (a -> Maybe a) -> Map k a -> Map k a
- updateMinWithKey :: (k -> a -> Maybe a) -> Map k a -> Map k a
- updateMaxWithKey :: (k -> a -> Maybe a) -> Map k a -> Map k a
- minView :: Map k a -> Maybe (a, Map k a)
- maxView :: Map k a -> Maybe (a, Map k a)
- minViewWithKey :: Map k a -> Maybe ((k, a), Map k a)
- maxViewWithKey :: Map k a -> Maybe ((k, a), Map k a)
- showTree :: (Show k, Show a) => Map k a -> String
- showTreeWith :: (k -> a -> String) -> Bool -> Bool -> Map k a -> String
- valid :: Ord k => Map k a -> Bool
Map type
A Map from keys k
to values a
.
Operators
(!) :: Ord k => Map k a -> k -> aSource
O(log n). Find the value at a key.
Calls error
when the element can not be found.
fromList [(5,'a'), (3,'b')] ! 1 Error: element not in the map fromList [(5,'a'), (3,'b')] ! 5 == 'a'
Query
O(1). Is the map empty?
Data.Map.null (empty) == True Data.Map.null (singleton 1 'a') == False
O(1). The number of elements in the map.
size empty == 0 size (singleton 1 'a') == 1 size (fromList([(1,'a'), (2,'c'), (3,'b')])) == 3
member :: Ord k => k -> Map k a -> BoolSource
O(log n). Is the key a member of the map? See also notMember
.
member 5 (fromList [(5,'a'), (3,'b')]) == True member 1 (fromList [(5,'a'), (3,'b')]) == False
notMember :: Ord k => k -> Map k a -> BoolSource
O(log n). Is the key not a member of the map? See also member
.
notMember 5 (fromList [(5,'a'), (3,'b')]) == False notMember 1 (fromList [(5,'a'), (3,'b')]) == True
lookup :: Ord k => k -> Map k a -> Maybe aSource
O(log n). Lookup the value at a key in the map.
The function will return the corresponding value as (
,
or Just
value)Nothing
if the key isn't in the map.
An example of using lookup
:
import Prelude hiding (lookup) import Data.Map employeeDept = fromList([("John","Sales"), ("Bob","IT")]) deptCountry = fromList([("IT","USA"), ("Sales","France")]) countryCurrency = fromList([("USA", "Dollar"), ("France", "Euro")]) employeeCurrency :: String -> Maybe String employeeCurrency name = do dept <- lookup name employeeDept country <- lookup dept deptCountry lookup country countryCurrency main = do putStrLn $ "John's currency: " ++ (show (employeeCurrency "John")) putStrLn $ "Pete's currency: " ++ (show (employeeCurrency "Pete"))
The output of this program:
John's currency: Just "Euro" Pete's currency: Nothing
findWithDefault :: Ord k => a -> k -> Map k a -> aSource
O(log n). The expression (
returns
the value at key findWithDefault
def k map)k
or returns default value def
when the key is not in the map.
findWithDefault 'x' 1 (fromList [(5,'a'), (3,'b')]) == 'x' findWithDefault 'x' 5 (fromList [(5,'a'), (3,'b')]) == 'a'
Construction
singleton :: k -> a -> Map k aSource
O(1). A map with a single element.
singleton 1 'a' == fromList [(1, 'a')] size (singleton 1 'a') == 1
Insertion
insert :: Ord k => k -> a -> Map k a -> Map k aSource
O(log n). Insert a new key and value in the map.
If the key is already present in the map, the associated value is
replaced with the supplied value. insert
is equivalent to
.
insertWith
const
insert 5 'x' (fromList [(5,'a'), (3,'b')]) == fromList [(3, 'b'), (5, 'x')] insert 7 'x' (fromList [(5,'a'), (3,'b')]) == fromList [(3, 'b'), (5, 'a'), (7, 'x')] insert 5 'x' empty == singleton 5 'x'
insertWith :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k aSource
O(log n). Insert with a function, combining new value and old value.
will insert the pair (key, value) into insertWith
f key value mpmp
if key does
not exist in the map. If the key does exist, the function will
insert the pair (key, f new_value old_value)
.
insertWith (++) 5 "xxx" (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "xxxa")] insertWith (++) 7 "xxx" (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a"), (7, "xxx")] insertWith (++) 5 "xxx" empty == singleton 5 "xxx"
insertWith' :: Ord k => (a -> a -> a) -> k -> a -> Map k a -> Map k aSource
Same as insertWith
, but the combining function is applied strictly.
This is often the most desirable behavior.
For example, to update a counter:
insertWith' (+) k 1 m
insertWithKey :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> Map k aSource
O(log n). Insert with a function, combining key, new value and old value.
will insert the pair (key, value) into insertWithKey
f key value mpmp
if key does
not exist in the map. If the key does exist, the function will
insert the pair (key,f key new_value old_value)
.
Note that the key passed to f is the same key passed to insertWithKey
.
let f key new_value old_value = (show key) ++ ":" ++ new_value ++ "|" ++ old_value insertWithKey f 5 "xxx" (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "5:xxx|a")] insertWithKey f 7 "xxx" (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a"), (7, "xxx")] insertWithKey f 5 "xxx" empty == singleton 5 "xxx"
insertWithKey' :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> Map k aSource
Same as insertWithKey
, but the combining function is applied strictly.
insertLookupWithKey :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> (Maybe a, Map k a)Source
O(log n). Combines insert operation with old value retrieval.
The expression (
)
is a pair where the first element is equal to (insertLookupWithKey
f k x map
)
and the second element equal to (lookup
k map
).
insertWithKey
f k x map
let f key new_value old_value = (show key) ++ ":" ++ new_value ++ "|" ++ old_value insertLookupWithKey f 5 "xxx" (fromList [(5,"a"), (3,"b")]) == (Just "a", fromList [(3, "b"), (5, "5:xxx|a")]) insertLookupWithKey f 7 "xxx" (fromList [(5,"a"), (3,"b")]) == (Nothing, fromList [(3, "b"), (5, "a"), (7, "xxx")]) insertLookupWithKey f 5 "xxx" empty == (Nothing, singleton 5 "xxx")
This is how to define insertLookup
using insertLookupWithKey
:
let insertLookup kx x t = insertLookupWithKey (\_ a _ -> a) kx x t insertLookup 5 "x" (fromList [(5,"a"), (3,"b")]) == (Just "a", fromList [(3, "b"), (5, "x")]) insertLookup 7 "x" (fromList [(5,"a"), (3,"b")]) == (Nothing, fromList [(3, "b"), (5, "a"), (7, "x")])
insertLookupWithKey' :: Ord k => (k -> a -> a -> a) -> k -> a -> Map k a -> (Maybe a, Map k a)Source
O(log n). A strict version of insertLookupWithKey
.
Delete/Update
delete :: Ord k => k -> Map k a -> Map k aSource
O(log n). Delete a key and its value from the map. When the key is not a member of the map, the original map is returned.
delete 5 (fromList [(5,"a"), (3,"b")]) == singleton 3 "b" delete 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] delete 5 empty == empty
adjust :: Ord k => (a -> a) -> k -> Map k a -> Map k aSource
O(log n). Update a value at a specific key with the result of the provided function. When the key is not a member of the map, the original map is returned.
adjust ("new " ++) 5 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "new a")] adjust ("new " ++) 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] adjust ("new " ++) 7 empty == empty
adjustWithKey :: Ord k => (k -> a -> a) -> k -> Map k a -> Map k aSource
O(log n). Adjust a value at a specific key. When the key is not a member of the map, the original map is returned.
let f key x = (show key) ++ ":new " ++ x adjustWithKey f 5 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "5:new a")] adjustWithKey f 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] adjustWithKey f 7 empty == empty
update :: Ord k => (a -> Maybe a) -> k -> Map k a -> Map k aSource
O(log n). The expression (
) updates the value update
f k mapx
at k
(if it is in the map). If (f x
) is Nothing
, the element is
deleted. If it is (
), the key Just
yk
is bound to the new value y
.
let f x = if x == "a" then Just "new a" else Nothing update f 5 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "new a")] update f 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] update f 3 (fromList [(5,"a"), (3,"b")]) == singleton 5 "a"
updateWithKey :: Ord k => (k -> a -> Maybe a) -> k -> Map k a -> Map k aSource
O(log n). The expression (
) updates the
value updateWithKey
f k mapx
at k
(if it is in the map). If (f k x
) is Nothing
,
the element is deleted. If it is (
), the key Just
yk
is bound
to the new value y
.
let f k x = if x == "a" then Just ((show k) ++ ":new a") else Nothing updateWithKey f 5 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "5:new a")] updateWithKey f 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] updateWithKey f 3 (fromList [(5,"a"), (3,"b")]) == singleton 5 "a"
updateLookupWithKey :: Ord k => (k -> a -> Maybe a) -> k -> Map k a -> (Maybe a, Map k a)Source
O(log n). Lookup and update. See also updateWithKey
.
The function returns changed value, if it is updated.
Returns the original key value if the map entry is deleted.
let f k x = if x == "a" then Just ((show k) ++ ":new a") else Nothing updateLookupWithKey f 5 (fromList [(5,"a"), (3,"b")]) == (Just "5:new a", fromList [(3, "b"), (5, "5:new a")]) updateLookupWithKey f 7 (fromList [(5,"a"), (3,"b")]) == (Nothing, fromList [(3, "b"), (5, "a")]) updateLookupWithKey f 3 (fromList [(5,"a"), (3,"b")]) == (Just "b", singleton 5 "a")
alter :: Ord k => (Maybe a -> Maybe a) -> k -> Map k a -> Map k aSource
O(log n). The expression (
) alters the value alter
f k mapx
at k
, or absence thereof.
alter
can be used to insert, delete, or update a value in a Map
.
In short :
.
lookup
k (alter
f k m) = f (lookup
k m)
let f _ = Nothing alter f 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a")] alter f 5 (fromList [(5,"a"), (3,"b")]) == singleton 3 "b" let f _ = Just "c" alter f 7 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "a"), (7, "c")] alter f 5 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "c")]
Combine
Union
union :: Ord k => Map k a -> Map k a -> Map k aSource
O(n+m).
The expression (
) takes the left-biased union of union
t1 t2t1
and t2
.
It prefers t1
when duplicate keys are encountered,
i.e. (
).
The implementation uses the efficient hedge-union algorithm.
Hedge-union is more efficient on (bigset `union
== unionWith
const
union
` smallset).
union (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == fromList [(3, "b"), (5, "a"), (7, "C")]
unionWith :: Ord k => (a -> a -> a) -> Map k a -> Map k a -> Map k aSource
O(n+m). Union with a combining function. The implementation uses the efficient hedge-union algorithm.
unionWith (++) (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == fromList [(3, "b"), (5, "aA"), (7, "C")]
unionWithKey :: Ord k => (k -> a -> a -> a) -> Map k a -> Map k a -> Map k aSource
O(n+m).
Union with a combining function. The implementation uses the efficient hedge-union algorithm.
Hedge-union is more efficient on (bigset `union
` smallset).
let f key left_value right_value = (show key) ++ ":" ++ left_value ++ "|" ++ right_value unionWithKey f (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == fromList [(3, "b"), (5, "5:a|A"), (7, "C")]
unions :: Ord k => [Map k a] -> Map k aSource
The union of a list of maps:
(
).
unions
== foldl
union
empty
unions [(fromList [(5, "a"), (3, "b")]), (fromList [(5, "A"), (7, "C")]), (fromList [(5, "A3"), (3, "B3")])] == fromList [(3, "b"), (5, "a"), (7, "C")] unions [(fromList [(5, "A3"), (3, "B3")]), (fromList [(5, "A"), (7, "C")]), (fromList [(5, "a"), (3, "b")])] == fromList [(3, "B3"), (5, "A3"), (7, "C")]
unionsWith :: Ord k => (a -> a -> a) -> [Map k a] -> Map k aSource
The union of a list of maps, with a combining operation:
(
).
unionsWith
f == foldl
(unionWith
f) empty
unionsWith (++) [(fromList [(5, "a"), (3, "b")]), (fromList [(5, "A"), (7, "C")]), (fromList [(5, "A3"), (3, "B3")])] == fromList [(3, "bB3"), (5, "aAA3"), (7, "C")]
Difference
difference :: Ord k => Map k a -> Map k b -> Map k aSource
O(n+m). Difference of two maps. Return elements of the first map not existing in the second map. The implementation uses an efficient hedge algorithm comparable with hedge-union.
difference (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == singleton 3 "b"
differenceWith :: Ord k => (a -> b -> Maybe a) -> Map k a -> Map k b -> Map k aSource
O(n+m). Difference with a combining function.
When two equal keys are
encountered, the combining function is applied to the values of these keys.
If it returns Nothing
, the element is discarded (proper set difference). If
it returns (
), the element is updated with a new value Just
yy
.
The implementation uses an efficient hedge algorithm comparable with hedge-union.
let f al ar = if al == "b" then Just (al ++ ":" ++ ar) else Nothing differenceWith f (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (3, "B"), (7, "C")]) == singleton 3 "b:B"
differenceWithKey :: Ord k => (k -> a -> b -> Maybe a) -> Map k a -> Map k b -> Map k aSource
O(n+m). Difference with a combining function. When two equal keys are
encountered, the combining function is applied to the key and both values.
If it returns Nothing
, the element is discarded (proper set difference). If
it returns (
), the element is updated with a new value Just
yy
.
The implementation uses an efficient hedge algorithm comparable with hedge-union.
let f k al ar = if al == "b" then Just ((show k) ++ ":" ++ al ++ "|" ++ ar) else Nothing differenceWithKey f (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (3, "B"), (10, "C")]) == singleton 3 "3:b|B"
Intersection
intersection :: Ord k => Map k a -> Map k b -> Map k aSource
O(n+m). Intersection of two maps.
Return data in the first map for the keys existing in both maps.
(
).
intersection
m1 m2 == intersectionWith
const
m1 m2
intersection (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == singleton 5 "a"
intersectionWith :: Ord k => (a -> b -> c) -> Map k a -> Map k b -> Map k cSource
O(n+m). Intersection with a combining function.
intersectionWith (++) (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == singleton 5 "aA"
intersectionWithKey :: Ord k => (k -> a -> b -> c) -> Map k a -> Map k b -> Map k cSource
O(n+m). Intersection with a combining function.
Intersection is more efficient on (bigset `intersection
` smallset).
let f k al ar = (show k) ++ ":" ++ al ++ "|" ++ ar intersectionWithKey f (fromList [(5, "a"), (3, "b")]) (fromList [(5, "A"), (7, "C")]) == singleton 5 "5:a|A"
Traversal
Map
map :: (a -> b) -> Map k a -> Map k bSource
O(n). Map a function over all values in the map.
map (++ "x") (fromList [(5,"a"), (3,"b")]) == fromList [(3, "bx"), (5, "ax")]
mapWithKey :: (k -> a -> b) -> Map k a -> Map k bSource
O(n). Map a function over all values in the map.
let f key x = (show key) ++ ":" ++ x mapWithKey f (fromList [(5,"a"), (3,"b")]) == fromList [(3, "3:b"), (5, "5:a")]
mapAccum :: (a -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)Source
O(n). The function mapAccum
threads an accumulating
argument through the map in ascending order of keys.
let f a b = (a ++ b, b ++ "X") mapAccum f "Everything: " (fromList [(5,"a"), (3,"b")]) == ("Everything: ba", fromList [(3, "bX"), (5, "aX")])
mapAccumWithKey :: (a -> k -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)Source
O(n). The function mapAccumWithKey
threads an accumulating
argument through the map in ascending order of keys.
let f a k b = (a ++ " " ++ (show k) ++ "-" ++ b, b ++ "X") mapAccumWithKey f "Everything:" (fromList [(5,"a"), (3,"b")]) == ("Everything: 3-b 5-a", fromList [(3, "bX"), (5, "aX")])
mapAccumRWithKey :: (a -> k -> b -> (a, c)) -> a -> Map k b -> (a, Map k c)Source
O(n). The function mapAccumR
threads an accumulating
argument through the map in descending order of keys.
mapKeys :: Ord k2 => (k1 -> k2) -> Map k1 a -> Map k2 aSource
O(n*log n).
is the map obtained by applying mapKeys
f sf
to each key of s
.
The size of the result may be smaller if f
maps two or more distinct
keys to the same new key. In this case the value at the smallest of
these keys is retained.
mapKeys (+ 1) (fromList [(5,"a"), (3,"b")]) == fromList [(4, "b"), (6, "a")] mapKeys (\ _ -> 1) (fromList [(1,"b"), (2,"a"), (3,"d"), (4,"c")]) == singleton 1 "c" mapKeys (\ _ -> 3) (fromList [(1,"b"), (2,"a"), (3,"d"), (4,"c")]) == singleton 3 "c"
mapKeysWith :: Ord k2 => (a -> a -> a) -> (k1 -> k2) -> Map k1 a -> Map k2 aSource
O(n*log n).
is the map obtained by applying mapKeysWith
c f sf
to each key of s
.
The size of the result may be smaller if f
maps two or more distinct
keys to the same new key. In this case the associated values will be
combined using c
.
mapKeysWith (++) (\ _ -> 1) (fromList [(1,"b"), (2,"a"), (3,"d"), (4,"c")]) == singleton 1 "cdab" mapKeysWith (++) (\ _ -> 3) (fromList [(1,"b"), (2,"a"), (3,"d"), (4,"c")]) == singleton 3 "cdab"
mapKeysMonotonic :: (k1 -> k2) -> Map k1 a -> Map k2 aSource
O(n).
, but works only when mapKeysMonotonic
f s == mapKeys
f sf
is strictly monotonic.
That is, for any values x
and y
, if x
< y
then f x
< f y
.
The precondition is not checked.
Semi-formally, we have:
and [x < y ==> f x < f y | x <- ls, y <- ls] ==> mapKeysMonotonic f s == mapKeys f s where ls = keys s
This means that f
maps distinct original keys to distinct resulting keys.
This function has better performance than mapKeys
.
mapKeysMonotonic (\ k -> k * 2) (fromList [(5,"a"), (3,"b")]) == fromList [(6, "b"), (10, "a")] valid (mapKeysMonotonic (\ k -> k * 2) (fromList [(5,"a"), (3,"b")])) == True valid (mapKeysMonotonic (\ _ -> 1) (fromList [(5,"a"), (3,"b")])) == False
Fold
foldWithKey :: (k -> a -> b -> b) -> b -> Map k a -> bSource
O(n). Fold the keys and values in the map, such that
.
For example,
foldWithKey
f z == foldr
(uncurry
f) z . toAscList
keys map = foldWithKey (\k x ks -> k:ks) [] map
let f k a result = result ++ "(" ++ (show k) ++ ":" ++ a ++ ")" foldWithKey f "Map: " (fromList [(5,"a"), (3,"b")]) == "Map: (5:a)(3:b)"
This is identical to foldrWithKey
, and you should use that one instead of
this one. This name is kept for backward compatibility.
foldrWithKey :: (k -> a -> b -> b) -> b -> Map k a -> bSource
O(n). Post-order fold. The function will be applied from the lowest value to the highest.
foldlWithKey :: (b -> k -> a -> b) -> b -> Map k a -> bSource
O(n). Pre-order fold. The function will be applied from the highest value to the lowest.
Conversion
O(n). Return all elements of the map in the ascending order of their keys.
elems (fromList [(5,"a"), (3,"b")]) == ["b","a"] elems empty == []
O(n). Return all keys of the map in ascending order.
keys (fromList [(5,"a"), (3,"b")]) == [3,5] keys empty == []
keysSet :: Map k a -> Set kSource
O(n). The set of all keys of the map.
keysSet (fromList [(5,"a"), (3,"b")]) == Data.Set.fromList [3,5] keysSet empty == Data.Set.empty
assocs :: Map k a -> [(k, a)]Source
O(n). Return all key/value pairs in the map in ascending key order.
assocs (fromList [(5,"a"), (3,"b")]) == [(3,"b"), (5,"a")] assocs empty == []
Lists
toList :: Map k a -> [(k, a)]Source
O(n). Convert to a list of key/value pairs.
toList (fromList [(5,"a"), (3,"b")]) == [(3,"b"), (5,"a")] toList empty == []
fromList :: Ord k => [(k, a)] -> Map k aSource
O(n*log n). Build a map from a list of key/value pairs. See also fromAscList
.
If the list contains more than one value for the same key, the last value
for the key is retained.
fromList [] == empty fromList [(5,"a"), (3,"b"), (5, "c")] == fromList [(5,"c"), (3,"b")] fromList [(5,"c"), (3,"b"), (5, "a")] == fromList [(5,"a"), (3,"b")]
fromListWith :: Ord k => (a -> a -> a) -> [(k, a)] -> Map k aSource
O(n*log n). Build a map from a list of key/value pairs with a combining function. See also fromAscListWith
.
fromListWith (++) [(5,"a"), (5,"b"), (3,"b"), (3,"a"), (5,"a")] == fromList [(3, "ab"), (5, "aba")] fromListWith (++) [] == empty
fromListWithKey :: Ord k => (k -> a -> a -> a) -> [(k, a)] -> Map k aSource
O(n*log n). Build a map from a list of key/value pairs with a combining function. See also fromAscListWithKey
.
let f k a1 a2 = (show k) ++ a1 ++ a2 fromListWithKey f [(5,"a"), (5,"b"), (3,"b"), (3,"a"), (5,"a")] == fromList [(3, "3ab"), (5, "5a5ba")] fromListWithKey f [] == empty
Ordered lists
toAscList :: Map k a -> [(k, a)]Source
O(n). Convert to an ascending list.
toAscList (fromList [(5,"a"), (3,"b")]) == [(3,"b"), (5,"a")]
toDescList :: Map k a -> [(k, a)]Source
O(n). Convert to a descending list.
fromAscList :: Eq k => [(k, a)] -> Map k aSource
O(n). Build a map from an ascending list in linear time. The precondition (input list is ascending) is not checked.
fromAscList [(3,"b"), (5,"a")] == fromList [(3, "b"), (5, "a")] fromAscList [(3,"b"), (5,"a"), (5,"b")] == fromList [(3, "b"), (5, "b")] valid (fromAscList [(3,"b"), (5,"a"), (5,"b")]) == True valid (fromAscList [(5,"a"), (3,"b"), (5,"b")]) == False
fromAscListWith :: Eq k => (a -> a -> a) -> [(k, a)] -> Map k aSource
O(n). Build a map from an ascending list in linear time with a combining function for equal keys. The precondition (input list is ascending) is not checked.
fromAscListWith (++) [(3,"b"), (5,"a"), (5,"b")] == fromList [(3, "b"), (5, "ba")] valid (fromAscListWith (++) [(3,"b"), (5,"a"), (5,"b")]) == True valid (fromAscListWith (++) [(5,"a"), (3,"b"), (5,"b")]) == False
fromAscListWithKey :: Eq k => (k -> a -> a -> a) -> [(k, a)] -> Map k aSource
O(n). Build a map from an ascending list in linear time with a combining function for equal keys. The precondition (input list is ascending) is not checked.
let f k a1 a2 = (show k) ++ ":" ++ a1 ++ a2 fromAscListWithKey f [(3,"b"), (5,"a"), (5,"b"), (5,"b")] == fromList [(3, "b"), (5, "5:b5:ba")] valid (fromAscListWithKey f [(3,"b"), (5,"a"), (5,"b"), (5,"b")]) == True valid (fromAscListWithKey f [(5,"a"), (3,"b"), (5,"b"), (5,"b")]) == False
fromDistinctAscList :: [(k, a)] -> Map k aSource
O(n). Build a map from an ascending list of distinct elements in linear time. The precondition is not checked.
fromDistinctAscList [(3,"b"), (5,"a")] == fromList [(3, "b"), (5, "a")] valid (fromDistinctAscList [(3,"b"), (5,"a")]) == True valid (fromDistinctAscList [(3,"b"), (5,"a"), (5,"b")]) == False
Filter
filter :: Ord k => (a -> Bool) -> Map k a -> Map k aSource
O(n). Filter all values that satisfy the predicate.
filter (> "a") (fromList [(5,"a"), (3,"b")]) == singleton 3 "b" filter (> "x") (fromList [(5,"a"), (3,"b")]) == empty filter (< "a") (fromList [(5,"a"), (3,"b")]) == empty
filterWithKey :: Ord k => (k -> a -> Bool) -> Map k a -> Map k aSource
O(n). Filter all keys/values that satisfy the predicate.
filterWithKey (\k _ -> k > 4) (fromList [(5,"a"), (3,"b")]) == singleton 5 "a"
partition :: Ord k => (a -> Bool) -> Map k a -> (Map k a, Map k a)Source
O(n). Partition the map according to a predicate. The first
map contains all elements that satisfy the predicate, the second all
elements that fail the predicate. See also split
.
partition (> "a") (fromList [(5,"a"), (3,"b")]) == (singleton 3 "b", singleton 5 "a") partition (< "x") (fromList [(5,"a"), (3,"b")]) == (fromList [(3, "b"), (5, "a")], empty) partition (> "x") (fromList [(5,"a"), (3,"b")]) == (empty, fromList [(3, "b"), (5, "a")])
partitionWithKey :: Ord k => (k -> a -> Bool) -> Map k a -> (Map k a, Map k a)Source
O(n). Partition the map according to a predicate. The first
map contains all elements that satisfy the predicate, the second all
elements that fail the predicate. See also split
.
partitionWithKey (\ k _ -> k > 3) (fromList [(5,"a"), (3,"b")]) == (singleton 5 "a", singleton 3 "b") partitionWithKey (\ k _ -> k < 7) (fromList [(5,"a"), (3,"b")]) == (fromList [(3, "b"), (5, "a")], empty) partitionWithKey (\ k _ -> k > 7) (fromList [(5,"a"), (3,"b")]) == (empty, fromList [(3, "b"), (5, "a")])
mapMaybe :: Ord k => (a -> Maybe b) -> Map k a -> Map k bSource
O(n). Map values and collect the Just
results.
let f x = if x == "a" then Just "new a" else Nothing mapMaybe f (fromList [(5,"a"), (3,"b")]) == singleton 5 "new a"
mapMaybeWithKey :: Ord k => (k -> a -> Maybe b) -> Map k a -> Map k bSource
O(n). Map keys/values and collect the Just
results.
let f k _ = if k < 5 then Just ("key : " ++ (show k)) else Nothing mapMaybeWithKey f (fromList [(5,"a"), (3,"b")]) == singleton 3 "key : 3"
mapEither :: Ord k => (a -> Either b c) -> Map k a -> (Map k b, Map k c)Source
O(n). Map values and separate the Left
and Right
results.
let f a = if a < "c" then Left a else Right a mapEither f (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) == (fromList [(3,"b"), (5,"a")], fromList [(1,"x"), (7,"z")]) mapEither (\ a -> Right a) (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) == (empty, fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")])
mapEitherWithKey :: Ord k => (k -> a -> Either b c) -> Map k a -> (Map k b, Map k c)Source
O(n). Map keys/values and separate the Left
and Right
results.
let f k a = if k < 5 then Left (k * 2) else Right (a ++ a) mapEitherWithKey f (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) == (fromList [(1,2), (3,6)], fromList [(5,"aa"), (7,"zz")]) mapEitherWithKey (\_ a -> Right a) (fromList [(5,"a"), (3,"b"), (1,"x"), (7,"z")]) == (empty, fromList [(1,"x"), (3,"b"), (5,"a"), (7,"z")])
split :: Ord k => k -> Map k a -> (Map k a, Map k a)Source
O(log n). The expression (
) is a pair split
k map(map1,map2)
where
the keys in map1
are smaller than k
and the keys in map2
larger than k
.
Any key equal to k
is found in neither map1
nor map2
.
split 2 (fromList [(5,"a"), (3,"b")]) == (empty, fromList [(3,"b"), (5,"a")]) split 3 (fromList [(5,"a"), (3,"b")]) == (empty, singleton 5 "a") split 4 (fromList [(5,"a"), (3,"b")]) == (singleton 3 "b", singleton 5 "a") split 5 (fromList [(5,"a"), (3,"b")]) == (singleton 3 "b", empty) split 6 (fromList [(5,"a"), (3,"b")]) == (fromList [(3,"b"), (5,"a")], empty)
splitLookup :: Ord k => k -> Map k a -> (Map k a, Maybe a, Map k a)Source
O(log n). The expression (
) splits a map just
like splitLookup
k mapsplit
but also returns
.
lookup
k map
splitLookup 2 (fromList [(5,"a"), (3,"b")]) == (empty, Nothing, fromList [(3,"b"), (5,"a")]) splitLookup 3 (fromList [(5,"a"), (3,"b")]) == (empty, Just "b", singleton 5 "a") splitLookup 4 (fromList [(5,"a"), (3,"b")]) == (singleton 3 "b", Nothing, singleton 5 "a") splitLookup 5 (fromList [(5,"a"), (3,"b")]) == (singleton 3 "b", Just "a", empty) splitLookup 6 (fromList [(5,"a"), (3,"b")]) == (fromList [(3,"b"), (5,"a")], Nothing, empty)
Submap
isSubmapOf :: (Ord k, Eq a) => Map k a -> Map k a -> BoolSource
O(n+m).
This function is defined as (
).
isSubmapOf
= isSubmapOfBy
(==)
isSubmapOfBy :: Ord k => (a -> b -> Bool) -> Map k a -> Map k b -> BoolSource
O(n+m).
The expression (
) returns isSubmapOfBy
f t1 t2True
if
all keys in t1
are in tree t2
, and when f
returns True
when
applied to their respective values. For example, the following
expressions are all True
:
isSubmapOfBy (==) (fromList [('a',1)]) (fromList [('a',1),('b',2)]) isSubmapOfBy (<=) (fromList [('a',1)]) (fromList [('a',1),('b',2)]) isSubmapOfBy (==) (fromList [('a',1),('b',2)]) (fromList [('a',1),('b',2)])
But the following are all False
:
isSubmapOfBy (==) (fromList [('a',2)]) (fromList [('a',1),('b',2)]) isSubmapOfBy (<) (fromList [('a',1)]) (fromList [('a',1),('b',2)]) isSubmapOfBy (==) (fromList [('a',1),('b',2)]) (fromList [('a',1)])
isProperSubmapOf :: (Ord k, Eq a) => Map k a -> Map k a -> BoolSource
O(n+m). Is this a proper submap? (ie. a submap but not equal).
Defined as (
).
isProperSubmapOf
= isProperSubmapOfBy
(==)
isProperSubmapOfBy :: Ord k => (a -> b -> Bool) -> Map k a -> Map k b -> BoolSource
O(n+m). Is this a proper submap? (ie. a submap but not equal).
The expression (
) returns isProperSubmapOfBy
f m1 m2True
when
m1
and m2
are not equal,
all keys in m1
are in m2
, and when f
returns True
when
applied to their respective values. For example, the following
expressions are all True
:
isProperSubmapOfBy (==) (fromList [(1,1)]) (fromList [(1,1),(2,2)]) isProperSubmapOfBy (<=) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
But the following are all False
:
isProperSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1),(2,2)]) isProperSubmapOfBy (==) (fromList [(1,1),(2,2)]) (fromList [(1,1)]) isProperSubmapOfBy (<) (fromList [(1,1)]) (fromList [(1,1),(2,2)])
Indexed
lookupIndex :: Ord k => k -> Map k a -> Maybe IntSource
O(log n). Lookup the index of a key. The index is a number from
0 up to, but not including, the size
of the map.
isJust (lookupIndex 2 (fromList [(5,"a"), (3,"b")])) == False fromJust (lookupIndex 3 (fromList [(5,"a"), (3,"b")])) == 0 fromJust (lookupIndex 5 (fromList [(5,"a"), (3,"b")])) == 1 isJust (lookupIndex 6 (fromList [(5,"a"), (3,"b")])) == False
findIndex :: Ord k => k -> Map k a -> IntSource
O(log n). Return the index of a key. The index is a number from
0 up to, but not including, the size
of the map. Calls error
when
the key is not a member
of the map.
findIndex 2 (fromList [(5,"a"), (3,"b")]) Error: element is not in the map findIndex 3 (fromList [(5,"a"), (3,"b")]) == 0 findIndex 5 (fromList [(5,"a"), (3,"b")]) == 1 findIndex 6 (fromList [(5,"a"), (3,"b")]) Error: element is not in the map
elemAt :: Int -> Map k a -> (k, a)Source
O(log n). Retrieve an element by index. Calls error
when an
invalid index is used.
elemAt 0 (fromList [(5,"a"), (3,"b")]) == (3,"b") elemAt 1 (fromList [(5,"a"), (3,"b")]) == (5, "a") elemAt 2 (fromList [(5,"a"), (3,"b")]) Error: index out of range
updateAt :: (k -> a -> Maybe a) -> Int -> Map k a -> Map k aSource
O(log n). Update the element at index. Calls error
when an
invalid index is used.
updateAt (\ _ _ -> Just "x") 0 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "x"), (5, "a")] updateAt (\ _ _ -> Just "x") 1 (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "x")] updateAt (\ _ _ -> Just "x") 2 (fromList [(5,"a"), (3,"b")]) Error: index out of range updateAt (\ _ _ -> Just "x") (-1) (fromList [(5,"a"), (3,"b")]) Error: index out of range updateAt (\_ _ -> Nothing) 0 (fromList [(5,"a"), (3,"b")]) == singleton 5 "a" updateAt (\_ _ -> Nothing) 1 (fromList [(5,"a"), (3,"b")]) == singleton 3 "b" updateAt (\_ _ -> Nothing) 2 (fromList [(5,"a"), (3,"b")]) Error: index out of range updateAt (\_ _ -> Nothing) (-1) (fromList [(5,"a"), (3,"b")]) Error: index out of range
deleteAt :: Int -> Map k a -> Map k aSource
O(log n). Delete the element at index.
Defined as (
).
deleteAt
i map = updateAt
(k x -> Nothing
) i map
deleteAt 0 (fromList [(5,"a"), (3,"b")]) == singleton 5 "a" deleteAt 1 (fromList [(5,"a"), (3,"b")]) == singleton 3 "b" deleteAt 2 (fromList [(5,"a"), (3,"b")]) Error: index out of range deleteAt (-1) (fromList [(5,"a"), (3,"b")]) Error: index out of range
Min/Max
findMin :: Map k a -> (k, a)Source
O(log n). The minimal key of the map. Calls error
is the map is empty.
findMin (fromList [(5,"a"), (3,"b")]) == (3,"b") findMin empty Error: empty map has no minimal element
findMax :: Map k a -> (k, a)Source
O(log n). The maximal key of the map. Calls error
is the map is empty.
findMax (fromList [(5,"a"), (3,"b")]) == (5,"a") findMax empty Error: empty map has no maximal element
deleteMin :: Map k a -> Map k aSource
O(log n). Delete the minimal key. Returns an empty map if the map is empty.
deleteMin (fromList [(5,"a"), (3,"b"), (7,"c")]) == fromList [(5,"a"), (7,"c")] deleteMin empty == empty
deleteMax :: Map k a -> Map k aSource
O(log n). Delete the maximal key. Returns an empty map if the map is empty.
deleteMax (fromList [(5,"a"), (3,"b"), (7,"c")]) == fromList [(3,"b"), (5,"a")] deleteMax empty == empty
deleteFindMin :: Map k a -> ((k, a), Map k a)Source
O(log n). Delete and find the minimal element.
deleteFindMin (fromList [(5,"a"), (3,"b"), (10,"c")]) == ((3,"b"), fromList[(5,"a"), (10,"c")]) deleteFindMin Error: can not return the minimal element of an empty map
deleteFindMax :: Map k a -> ((k, a), Map k a)Source
O(log n). Delete and find the maximal element.
deleteFindMax (fromList [(5,"a"), (3,"b"), (10,"c")]) == ((10,"c"), fromList [(3,"b"), (5,"a")]) deleteFindMax empty Error: can not return the maximal element of an empty map
updateMin :: (a -> Maybe a) -> Map k a -> Map k aSource
O(log n). Update the value at the minimal key.
updateMin (\ a -> Just ("X" ++ a)) (fromList [(5,"a"), (3,"b")]) == fromList [(3, "Xb"), (5, "a")] updateMin (\ _ -> Nothing) (fromList [(5,"a"), (3,"b")]) == singleton 5 "a"
updateMax :: (a -> Maybe a) -> Map k a -> Map k aSource
O(log n). Update the value at the maximal key.
updateMax (\ a -> Just ("X" ++ a)) (fromList [(5,"a"), (3,"b")]) == fromList [(3, "b"), (5, "Xa")] updateMax (\ _ -> Nothing) (fromList [(5,"a"), (3,"b")]) == singleton 3 "b"
updateMinWithKey :: (k -> a -> Maybe a) -> Map k a -> Map k aSource
O(log n). Update the value at the minimal key.
updateMinWithKey (\ k a -> Just ((show k) ++ ":" ++ a)) (fromList [(5,"a"), (3,"b")]) == fromList [(3,"3:b"), (5,"a")] updateMinWithKey (\ _ _ -> Nothing) (fromList [(5,"a"), (3,"b")]) == singleton 5 "a"
updateMaxWithKey :: (k -> a -> Maybe a) -> Map k a -> Map k aSource
O(log n). Update the value at the maximal key.
updateMaxWithKey (\ k a -> Just ((show k) ++ ":" ++ a)) (fromList [(5,"a"), (3,"b")]) == fromList [(3,"b"), (5,"5:a")] updateMaxWithKey (\ _ _ -> Nothing) (fromList [(5,"a"), (3,"b")]) == singleton 3 "b"
minView :: Map k a -> Maybe (a, Map k a)Source
O(log n). Retrieves the value associated with minimal key of the
map, and the map stripped of that element, or Nothing
if passed an
empty map.
minView (fromList [(5,"a"), (3,"b")]) == Just ("b", singleton 5 "a") minView empty == Nothing
maxView :: Map k a -> Maybe (a, Map k a)Source
O(log n). Retrieves the value associated with maximal key of the
map, and the map stripped of that element, or Nothing
if passed an
maxView (fromList [(5,"a"), (3,"b")]) == Just ("a", singleton 3 "b") maxView empty == Nothing
minViewWithKey :: Map k a -> Maybe ((k, a), Map k a)Source
O(log n). Retrieves the minimal (key,value) pair of the map, and
the map stripped of that element, or Nothing
if passed an empty map.
minViewWithKey (fromList [(5,"a"), (3,"b")]) == Just ((3,"b"), singleton 5 "a") minViewWithKey empty == Nothing
maxViewWithKey :: Map k a -> Maybe ((k, a), Map k a)Source
O(log n). Retrieves the maximal (key,value) pair of the map, and
the map stripped of that element, or Nothing
if passed an empty map.
maxViewWithKey (fromList [(5,"a"), (3,"b")]) == Just ((5,"a"), singleton 3 "b") maxViewWithKey empty == Nothing
Debugging
showTree :: (Show k, Show a) => Map k a -> StringSource
O(n). Show the tree that implements the map. The tree is shown
in a compressed, hanging format. See showTreeWith
.
showTreeWith :: (k -> a -> String) -> Bool -> Bool -> Map k a -> StringSource
O(n). The expression (
) shows
the tree that implements the map. Elements are shown using the showTreeWith
showelem hang wide mapshowElem
function. If hang
is
True
, a hanging tree is shown otherwise a rotated tree is shown. If
wide
is True
, an extra wide version is shown.
Map> let t = fromDistinctAscList [(x,()) | x <- [1..5]] Map> putStrLn $ showTreeWith (\k x -> show (k,x)) True False t (4,()) +--(2,()) | +--(1,()) | +--(3,()) +--(5,()) Map> putStrLn $ showTreeWith (\k x -> show (k,x)) True True t (4,()) | +--(2,()) | | | +--(1,()) | | | +--(3,()) | +--(5,()) Map> putStrLn $ showTreeWith (\k x -> show (k,x)) False True t +--(5,()) | (4,()) | | +--(3,()) | | +--(2,()) | +--(1,())