ghc-9.6.3: The GHC API
Safe HaskellSafe-Inferred




tcSyntaxOp Source #


:: CtOrigin 
-> SyntaxExprRn 
-> [SyntaxOpType]

shape of syntax operator arguments

-> ExpRhoType

overall result type

-> ([TcSigmaType] -> [Mult] -> TcM a)

Type check any arguments, takes a type per hole and a multiplicity per arrow in the shape.

-> TcM (a, SyntaxExprTc) 

Typecheck a syntax operator The operator is a variable or a lambda at this stage (i.e. renamer output)t

tcSyntaxOpGen :: CtOrigin -> SyntaxExprRn -> [SyntaxOpType] -> SyntaxOpType -> ([TcSigmaTypeFRR] -> [Mult] -> TcM a) -> TcM (a, SyntaxExprTc) Source #

Slightly more general version of tcSyntaxOp that allows the caller to specify the shape of the result of the syntax operator

data SyntaxOpType Source #

What to expect for an argument to a rebindable-syntax operator. Quite like Type, but allows for holes to be filled in by tcSyntaxOp. The callback called from tcSyntaxOp gets a list of types; the meaning of these types is determined by a left-to-right depth-first traversal of the SyntaxOpType tree. So if you pass in

SynAny `SynFun` (SynList `SynFun` SynType Int) `SynFun` SynAny

you'll get three types back: one for the first SynAny, the element type of the list, and one for the last SynAny. You don't get anything for the SynType, because you've said positively that it should be an Int, and so it shall be.

You'll also get three multiplicities back: one for each function arrow. See also Note [Linear types] in Multiplicity.

This is defined here to avoid defining it in GHC.Tc.Gen.Expr boot file.



Any type


A rho type, skolemised or instantiated as appropriate


A list type. You get back the element type of the list

SynFun SyntaxOpType SyntaxOpType infixr 0

A function.

SynType ExpType

A known type.

synKnownType :: TcType -> SyntaxOpType Source #

Like SynType but accepts a regular TcType